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Commit 256e1c7d authored by Julien Fontchastagner's avatar Julien Fontchastagner
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coquille phi

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...@@ -50,10 +50,10 @@ Si nous considérons un système électromagnétique alimenté par des tensions ...@@ -50,10 +50,10 @@ Si nous considérons un système électromagnétique alimenté par des tensions
Par exemple, le champ magnétique sera : Par exemple, le champ magnétique sera :
$$\begin{aligned}{\bf h}(x,y,z,t) &= {\bf h}(x,y,z)\\,\cos(\omega t + \varphi)\\\\ &= \sqrt{2}~{\bf h\_{\text{eff}}}(x,y,z)\\,\cos(\omega t + \varphi) \\\\ &= \mathcal{Re}[\sqrt{2}~{\bf h\_{\text{eff}}}(x,y,z)\\,\text{e}^{j\varphi}\\,\text{e}^{j\omega\\,t}]\end{aligned}$$ $$\begin{aligned}{\bf h}(x,y,z,t) &= {\bf h}(x,y,z)\\,\cos(\omega t + \varphi(x,y,z))\\\\ &= \sqrt{2}~{\bf h\_{\text{eff}}}(x,y,z)\\,\cos(\omega t + \varphi(x,y,z)) \\\\ &= \mathcal{Re}[\sqrt{2}~{\bf h\_{\text{eff}}}(x,y,z)\\,\text{e}^{j\varphi(x,y,z)}\\,\text{e}^{j\omega\\,t}]\end{aligned}$$
Soit : Soit :
$$\underline{{\bf h}}(x,y,z) = {\bf h\_{\text{eff}}}(x,y,z)\\,\text{e}^{j\varphi}$$ $$\underline{{\bf h}}(x,y,z) = {\bf h\_{\text{eff}}}(x,y,z)\\,\text{e}^{j\varphi(x,y,z)}$$
avec avec
$${\bf h\_{\text{eff}}}(x,y,z) = \begin{pmatrix} h\_{x_\text{eff}} \\\\ h\_{y_\text{eff}} \\\\ h\_{z_\text{eff}}\end{pmatrix} = \begin{pmatrix} \sqrt{\frac{1}{T}\\,\int\_{0}^{T} h\_{x}^2(x,y,z,t)\\,\text{d} t}\\\\[1em]\sqrt{\frac{1}{T}\\,\int\_{0}^{T} h\_{y}^2(x,y,z,t)\\,\text{d} t}\\\\[1em]\sqrt{\frac{1}{T}\\,\int\_{0}^{T} h\_{z}^2(x,y,z,t)\\,\text{d} t}\end{pmatrix}$$ $${\bf h\_{\text{eff}}}(x,y,z) = \begin{pmatrix} h\_{x_\text{eff}} \\\\ h\_{y_\text{eff}} \\\\ h\_{z_\text{eff}}\end{pmatrix} = \begin{pmatrix} \sqrt{\frac{1}{T}\\,\int\_{0}^{T} h\_{x}^2(x,y,z,t)\\,\text{d} t}\\\\[1em]\sqrt{\frac{1}{T}\\,\int\_{0}^{T} h\_{y}^2(x,y,z,t)\\,\text{d} t}\\\\[1em]\sqrt{\frac{1}{T}\\,\int\_{0}^{T} h\_{z}^2(x,y,z,t)\\,\text{d} t}\end{pmatrix}$$
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